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(-9x+3x^2)/(-x)=0
Domain of the equation: (-x)!=0We add all the numbers together, and all the variables
x!=0/-1
x!=0
x∈R
(-9x+3x^2)/(-1x)=0
We multiply all the terms by the denominator
(-9x+3x^2)=0
We get rid of parentheses
3x^2-9x=0
a = 3; b = -9; c = 0;
Δ = b2-4ac
Δ = -92-4·3·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-9}{2*3}=\frac{0}{6} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+9}{2*3}=\frac{18}{6} =3 $
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